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how many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution

how many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution?
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x(40%)+(20-x)(65%)=20(50%) .4x+13-.65x=10 ... 3=.25x ... 12=x
answered by: fatma kaya
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how many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution
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