according to the chegg rule we have to answer only four sub parts at a time.
MetroPCS LTE 9:16 PM 9 webassign.net Object A has mass mA-7 kg and initial momentum A<18,-6, 0> kg m/s, just before it strikes object B, which has mass mB 10 kg. Just before the collision...
Object A has mass mA = 9 kg and initial momentum PA = < 15,-8,0 > kgm/s, just before it strikes object B, which has mass mg = 12 kg. Just before the collision object B has initial momentum 8,1 = < 4,7,0 > kg. m/s. Consider a system consisting of both objects A and B. What is the total initial momentum of this system, just before the collision? sysj = (19,-1,0) kg.m/s The forces that A and B exert...
Object A has mass mA = 7 kg and initial momentum A,i = < 15, -8, 0 > kg· m/s, just before it strikes object B, which has massmB = 10 kg. Justbefore thecollision object B has initial momentumB,i =<6, 7, 0> kg · m/s.Consider a system consisting of both objects Aand B. What is the total initial momentum of this system, justbefore the collision?sys,i = <, , 0 > kg · m/sThe forces that A and B exert on...
kg m/s hits a nomentum of the ball is(5 wall and bounces straight back with the sam B. +4.0 kg-m/s C8.0kgm/s. Questions 2, 3; A 6.0 kg object moving north at a speed of 3.0 m/s, collides with a 4.0kg objot moving sous D.-8.0kgm/s Enone of the with speed of 6.0 m/s. On collision, the two objects stick togetber and move s one cbject 2. The magnitude of the sum of the linear momentum of the two objects just aher...
A6.65 kg bowling bal moving at 10.0 m/ s colides with a 1.60 kg bowling pin, scattering It with a speed of 8.00 m/s and at an angle of 36.0% with respect to the initial direction of the (a) Calculate the final velocity (magnitude in m/s and direction in degrees velocity (magnitude in m/s and direction in degrees counterclockwise from the original direction) of the bowling ball magnitude m/s direction counterdlockwise from the original direction of the bowling ball (b)...
In outer space rock 1 with mass 9 kg and velocity <3400, -3100, 3400> m/s, struck rock 2, which was at rest. After the collision, rock 1's velocity is <2900, -2300, 3700> m/s. What is the final momentum of rock 2? P 2 = > kg-m/s Before the collision, what was the kinetic energy of rock 1? Kli= Before the collision, what was the kinetic energy of rock 2? K2 = After the collision, what is the kinetic energy of...
1. Two asteroids collide head-on and stick together. Before the collision, asteroid A (mass 1,000 kg) moved at 100 m/s and asteroid B (mass 2,000 kg) moved at 80 m/s in the opposite direction. Use momentum conservation (make a complete Momentum chart) to find the velocity of the asteroids after the collision. 2. Two asteroids identical to those in (1) collide at right angles and stick together. "Collide at right angles" means that their initial velocities were perpendicular to each...
A car of mass 2400 kg collides with a truck of mass 4600 kg, and just after the collision the car and truck slide along, stuck together, with no rotation. The car's velocity just before the collision was <38, 0, 0 m/s, and the truck's velocity just before the collision was C-19, 0, 26> m/s. (a) Your first task is to determine the velocity of the stuck-together car and truck just after the collision. What system and principle should you...
** An object of mass m1 =7.1 kg moving at 5.3 m/s strikes a stationary second object of unknown mass. After an elastic collision, the first object is observed moving at 3.71 m/s at an angle of -47° with respect to the original line of motion. What is the energy of the second object? Submit Answer Tries 0/8 What is the magnitude of the second object's momentum after the collision? Submit Answer Tries 0/8 At what angle did the second...
Problem 1: An object with mass m = 2 kg slides down a frictionless incline that makes a 25° with the horizontal (as in the figure). At the bottom of the incline, object 1 continues to travel along the rough surface with Hk = 0.4. Object 2, m2 = 5 kg is d = 3 m away from the bottom of the incline. Object 2 is initially at rest. The height of the incline is h = 4m. h 0...
Problem 1: An object with mass m = 2 kg slides down a frictionless incline that makes a 25° with the horizontal (as in the figure). At the bottom of the incline, object I continues to travel along the rough surface with Hk = 0.4. Object 2, m2 = 5 kg is d = 3 m away from the bottom of the incline. Object 2 is initially at rest. The height of the incline is h = 4m. h 2...
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