Solve: 2 sin x - 1 = 0 for 0 degrees is less than or equal to x is less than 360 degrees
Solve: sin2 x = cos2 x for 0 degrees is less than or equal to x is less than 360 degrees.
Solve each equation for 0 is less than and equal to "x" is less than and equal to 3603sinx = 2cos^{2}x-----I don't know how to solve this equation...this is what I have, but I don't know if I'm on the right track or not3sinx = 1 - 2sin^{2}x3sinx - 1 + 2sin^{2}x = 02sin^{2}x + 3sinx - 1 = 0sinx(3 + 2sinx) = 1...and if I am, what do I do next now?-----The answers are:30 and 150 degrees
Solve for x where x is a real number, sin 2x = sin x, 0 less than or equal to x less than or equal to 2 pi
For which angles beta, with 0 degrees less than/equal to beta less than/equal to 180 degrees,is sin 3beta equal to -1?a) 30 degress and 150 degreesb) 60 and 120 degreesc) 90 degreesd) 0 and 120 degreesI think it is C because sin of (3 x 90 = 270) 270 degrees is -1?Did I do this right? Or did I do something that cannot be done?Thank you.
1.) Find the solution set of 2sin squared θ-1= 0 if 180 degrees is less than or equal to θ is less than or equal to 360 degrees2.) prove: 2cotθ/cot squared θ -1 = sin2 θ sec2 θ
Solve to the nearest minute: x is greater than or equal to 0 and less than 360.3sec^2 x-8tan-6=cotx
Solve each equation on the interval:0 is less than and equal to theta is less than and equal to 360--2sin2x = 1-----My Answers:Let y represent 2x2siny = 12siny/2 = 1/2siny = 1/2y = sin^-1(1/2)y = 302x = 302x/2 = 30/2x = 15 (Quadrant 1)Quadrant 2180 - theta= 180 - 30= 1502x = 1502x/2 = 150/2x = 75Therefore, x = 15 and 75 degrees---Book's Answers:15, 75, 195, 255---My Problem:I'm asking how do you get 195 and 255 degrees if the equation...
Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360--cos^2x - 1 = sin^2x--Attempt:cos^2x - 1 - sin^2x = 0cos^2x - 1 - (1 - cos^2x) = 0cos^2x - 1 - 1 + cos^2x = 02cos^2x - 2 = 0(2cos^2x/2)= (-2/2)cos^2x = -1cosx = square root of -1And I can't do anything with this now...what am I doing wrong?--Textbook answers:0, 180, 360--
Solve: sin x - 2sin x cos x = 0 for 0 is less than or equal to x is less than 2pi.
Find the value of x in the interval 0 is less than or equal to x and 360 is greater than or equal to x which satisfies the equation cos x - 2 cos x sin x.