1.Ammonia is created in the Haber process in a rigid container (nitrogen gas plus hydrogen gas react to form ammonia gas). 2.0 moles of hydrogen gas are mixed with 4.0 moles of nitrogen gas. The initial pressure exerted on the container is 5.0 atm. Assuming the reaction runs to completion, what will the pressure (in atm) on the vessel be after the reaction takes place?
2.Pentane gas reacts with oxygen gas to give carbon dioxide gas and water vapor (gas). If you mix pentane and oxygen in the correct stoichiometric ratio, and if the total pressure of the mixture is 180 mm Hg, what are the partial pressures of pentane ( mmHg) and oxygen ( mm Hg)? If the temperature and volume do not change, what is the pressure of the water vapor ( mm Hg) after reaction
can you please show your work,thank you!
The reaction between nitrogen gas and hydrogen gas to produce ammonia gas is
It is being assumed that the reaction runs to completion after starting with 2.0 moles of Hydrogen gas and 4.0 moles of nitrogen gas.
According to the balanced reaction, 1 mole of N2 gas reacts with 3 moles of H2 gas to form 2 moles of ammonia gas.
Hence, given that
The pressure exerted is 5.0 atm initially when the number of moles of gas in the container is
assuming constant volume and temperature.
Initial pressure in the container is
Hence, assuming the gases behave ideally
Note that V, T and R are all constants. Hence, the pressure in the container is only dependent on the number of moles of gas.
i.e pressure is directly proportional to the number of moles of gas. So we can write
The number of moles of nitrogen gas that will react with 2.0 mol of H2 gas is
Hence, all 2.0 mol of H2 will react with 0.67 mol of N2 to form ammonia gas. Here H2 is the limiting reactant.
Note that 3 mol of H2 forms 2 mol NH3. Hence, the number of moles of ammonia gas formed from 2 mol H2 is
Hence, the constituents in the chamber after completion is
(completely consumed as it is the limiting reactant)
(nitrogen gas is in excess, hence, there is 3.33 mol leftover after completion)
Hence, the total number of moles of gas after completion of reaction is
Hence, the final pressure in the container is
Hence, the pressure in the container at completion of reaction is about 3.9 atm.
The balanced reaction between pentane and oxygen to produce water and CO2 is
It is given that pentane and oxygen are being mixed in correct stoichiometric ratio i.e. 1 mol of pentane per 8 mol of oxygen gas.
Hence, the mole fraction of pentane and oxygen in the mixture is
Total pressure of the pentane and oxygen gas mixture,
Since the partial pressures of the gas is directly proportional to their mole fractions, the partial pressures are given by
Hence, the partial pressures of oxygen and pentane gas are 160 mmHg and 20 mmHg respectively.
After the reaction goes to completion at constant temperature and volume., we get 5 moles CO2 and 6 moles of H2O gases.(Note that since the reactant are taken in stoichiometric ratio, they are completely exhausted at completion)
We know that 9 moles of reactants resulted in a total pressure of 180 mmHg. Hence, 5 mol CO2 + 6 mol H2O =11 mol of products will result in a total pressure of
mole fraction of H2O gas at completion is
Hence, the partial pressure of H2O vapor at completion can be calculated as
Hence, the partial pressure of H2O at completion of reaction is 120 mmHg.
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