To find the height of the ball after
Hence, the Reqd. Height #=-16+90=74feet.
A soccer ball is kicked from ground level with an initial velocity of 90 feet per second. The equation #h=-16t^2+90t# gives the height h of the ball after t seconds. What is the height after 1 second?
The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 80 feet per second is f (t) = -16t^2 + 80t + 6. According to Rolle's Theorem, what must be the velocity at some time in the interval (2, 3)?ft/sec?& Find that time t?I believe i need to take the 1st derivative which is -32t+80 equal to zero so t=-80/32? and for ft/sec plug in 2...
The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 80 feet per second is f (t) = -16t^2 + 80t + 6.According to Rolle's Theorem, what must be the velocity at some time in the interval (2, 3)?ft/sec?& Find that time t?I believe i need to take the 1st derivative which is -32t+80 equal to zero so t=-80/32? and for ft/sec plug in 2 for...
A soccer ball is kicked from the ground with an initial speed of 19.9 m/s at an upward angle of 48.1°. A player 50.8 m away in the direction of the kick starts runningto meet the ball at that instant. What must be his average speed if he is to meet the ball just before it hits the ground? Neglect air resistance.
The equation h=-16t^2+47t+3 gives the height h, in feet, of a football as a function of time t, in seconds, after it is kicked. How long does it take for the football to hit the ground?
an object is launched from ground level with an initial velocity of 400 feet per second. To the nearest tenth off a second, how long does it take the object to reach a height off 650 feet?
Q. A soccer ball is kicked from the ground. When it reaches a height of 5.74 m, the velocity is v=5.86i+7.50j m/s. a) Determine the maximum height that the ball reaches. b) Determine the total horizontal distance travelled by the ball. c) What is the speed of the soccer ball just before it hits the ground? ok first of all i dont get this given velocity equation (v=5.86i+7.50j m/s). why are there unit vectors i and j? This is what...
If a metal ball is thrown downward with an initial velocity of 22 feet per second (15mph)from a 100 foot water tower, it's height h in feet above the ground after t seconds is modeled by h(t)=-16t^2-22t+100Determine when the height of the ball is 62 feet.
The formula h=48t-16t^2 gives the height, h, in feet, of an object projected into the air after t seconds. If an object is propelled upward, at what time(s) will it reach a height of 32 feet above the ground?
My question is given the equation s=-16t^2+initial velocity x t+initial height, a rocket is fired upward from ground level with an initial velocity of 1600 feet/sec. When does the rocket reach its maximum height and how high is it at that time?
The equation h=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s,where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 120ft. Put in h for 120, rearrange it into quadratic form, and solve. I recommend the quadradratic equation.