3).
a) From the given model M1,we have
Total = n = (70+10+10+10) = 100, True negative (TN) = 70 , True positive (TP) = 10 , False negative (FN) = 10 , False positive (FP) = 10
So, Accuracy = (TP+TN)/n = (10+70)/100 = 0.8,
Error Rate = (FP+FN)/n = (10+10)/100 = 0.2
b) From the given model M2, we have
Total = n = 70+0+20+10 = 100 , TN = 70 ,TP = 10, FN = 20 , FP = 0. So,
Accuracy = (TP + TN)/n = (10+70)/100 = 0.8,
Error Rate = (FP + FN)/n = (0+20)/100 = 0.2.
c) Cost for model M1 = 70(-1) + 10(100) + 10(1) +10(0)
= ( -70+1000+10+0) = 940
Cost for model M2 = 70(-1) + 0(100) + 20(1) + 10(0)
= (-70+0+20+0) = (-50).
Answer the following questions 3. (a) Consider the contingency table below and compute the ACCURACY rate...
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