We have that:
dy/dx=sin(x)cos(y)What is the solution to the equation at (0,(2n+1)π/2) where n is any integer?I know that you need to move common variables to the same side and then take the integral of both sides but I can't seem to be able to get y alone after that.Thanks.
Find dy/dx for y=sin(3x+4y)
If #dy/dx=3sin(3x)=e^(3x), and y(x=0)=0#, find #y(x)#
How do I integrate sin (x+y)? I know the answer is 0 because I used Maple. The "(x+y)" is really tripping me up. Anyone who can help is greatly appreciated.
if x=e^(2t) and y=sin(2t), then (dy)/(dx)
x dx dy + y) dx dy 0 (b (d a)(c) Answer: (a) x dx dy + y) dx dy 0 (b (d a)(c) Answer: (a)
If y= Arcsin(3x/4), then dy/dx= ?