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If #f(x)= 1/x # and #g(x) = 1/x #, what is #f'(g(x)) #?

If #f(x)= 1/x # and #g(x) = 1/x #, what is #f'(g(x)) #?
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ReportAnswer #1

#-x^2#

Explanation:

I'll assume no error in the statement of the question.

#f'(x) = -1/x^2#

Therefore,

#f'(g(x)) = -1/(g(x))^2 = -1/(1/x)^2 = -x^2#

answered by: Jim H
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If #f(x)= 1/x # and #g(x) = 1/x #, what is #f'(g(x)) #?
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