Freezing point depression constant for the the water is 1.86 K.Kg/mole
molality of the the solution is
For NaCl is 1 Mole/Kg of solution
For Mixture of NaCl and MgCl2 is 2 Mole/Kg of solution
For the calcium magnessium acetate is 1 Mole/Kg of solution
the molality is same in each of the three cases so the depression in the freezing point is same for all cases
Kf is the freezing point depression constant
m is the molality of the solution
freezing point of pure water is 273.15 K
hence the depression in the freezing point is 1.86 K for the NaCl and Calcium Magnesium Acetate solution
new freezing point of the solution is 273.15-1.86=271.29 K
For MgCl2 and NaCl both are one mole
= 1.86*2 = 3.72 K
the new freezing point is 273.15 - 3.72 = 269.43 K
for the case where all three are present in the solution hence the concentration of the solution now becomes 3 moles/Kg
new freezing point depression is
= 7.44 K
new freezing point is 273.15 - 7.44 = 265.71 K
ratio of moles of salts to the boiling point depression
Answere no 2
As the only solute is lost hence only solute moles will decrease
As the solvent is not lost only solute is lost hence molarity as well as molality will decrease
As the molality is decreasing because of decrease in moles of the solute so freezing point depression will also decrease
molar mass is the constant quantity so the it will not decrease because molar mass for one mole of substance is constant
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