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A ball with a mass of #70 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #49 (kg)/s^2# and was compressed by #7/6 m# when the ball was released. How high will the ball go?

A ball with a mass of #70 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #49 (kg)/s^2# and was compressed by #7/6 m# when the ball was released. How high will the ball go?
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ReportAnswer #1

The height is #=48.61m#

Explanation:

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The spring constant is #k=49kgs^-2#

The compression is #x=7/6m#

The potential energy in the spring is

#PE=1/2kx^2=1/2*49*(7/6)^2=33.35J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=(h) m#

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

The mass of the ball is #=0.070kg#

The acceleration due to gravity is #g=9.8ms^-2#

#PE_(ball)=33.35=0.070*9.8*h#

The height is #h=33.35*1/(0.070*9.8)#

#=48.61m#

answered by: Narad T.
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A ball with a mass of #70 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #49 (kg)/s^2# and was compressed by #7/6 m# when the ball was released. How high will the ball go?
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