The solution set is #(-6,-8)#.
We've got #3x-y=-10#, and #x-y=2#
So now, we can take #x-y=2# as #y-x=-2#.
Now simply add the two equations:
#(3x-y)+(y-x)=-10+(-2)#
#2x=-12#
#x=-6#
So if #x=-6#, #y# can be found by substitution:
#3(-6)-y=-10#
#-18-y=-10#
#-y=8#
#y=-8#
So here, #x=-6, y=-8#, and the solution set is #(-6,-8)#.
How do you solve the system of equations #3x - y = - 10# and #x - y = 2# by elimination?