Problem

A 5.0-m-long rod is stretched 0.10 m by a force. What is the strain in the rod?

A 5.0-m-long rod is stretched 0.10 m by a force. What is the strain in the rod?

Step-by-Step Solution

Solution 1

Strain in the rod is equal to the change in its length divided by its original length,

$$ \text { strain }=\frac{\Delta l}{l} $$

Here, \(\Delta l\) is the change in the length of the rod and \(l\) is its original length.

Substitute \(0.10 \mathrm{~m}\) for \(\Delta /\) and \(5.0 \mathrm{~m}\) for \(l\),

$$ \begin{aligned} \text { strain } &=\frac{0.10 \mathrm{~m}}{5.0 \mathrm{~m}} \\ &=0.02 \end{aligned} $$

Therefore, strain in the rod is \(0.02\).

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