Problem

# A circuit has three resistors connected in series. Resistor R2 has a resistance of 220 Ω a...

A circuit has three resistors connected in series. Resistor R2 has a resistance of 220 Ω and a voltage drop of 44 V. What is the current flow through resistor R3?

#### Step-by-Step Solution

Solution 1

The value of the resistance in the series circuit is $$\mathrm{R}_{2}=220 \Omega$$.

In the series circuit, the voltage drop across the resistor $$R_{2}$$ is $$\mathrm{E}_{2}=44 \mathrm{~V}$$.

In the series circuit, the current flowing is equal in all the elements of the circuit,

From Ohm's law to the resistor $$R_{2}$$, the current $$I$$ flowing across it is given by

$$\mathrm{I}=\frac{\mathrm{E}_{2}}{\mathrm{R}_{2}}$$

$$=\frac{44}{220}$$

$$=0.2 \mathrm{~A}$$

Hence, the current flowing through the resistor $$\mathrm{R}_{2}$$ is

$$\mathrm{I}=0.2 \mathrm{~A}$$.