Problem

A circuit has three resistors connected in series. Resistor R2 has a resistance of 220 Ω a...

A circuit has three resistors connected in series. Resistor R2 has a resistance of 220 Ω and a voltage drop of 44 V. What is the current flow through resistor R3?

Step-by-Step Solution

Solution 1

The value of the resistance in the series circuit is \(\mathrm{R}_{2}=220 \Omega\).

In the series circuit, the voltage drop across the resistor \(R_{2}\) is \(\mathrm{E}_{2}=44 \mathrm{~V}\).

In the series circuit, the current flowing is equal in all the elements of the circuit,

From Ohm's law to the resistor \(R_{2}\), the current \(I\) flowing across it is given by

\(\mathrm{I}=\frac{\mathrm{E}_{2}}{\mathrm{R}_{2}}\)

\(=\frac{44}{220}\)

\(=0.2 \mathrm{~A}\)

Hence, the current flowing through the resistor \(\mathrm{R}_{2}\) is

\(\mathrm{I}=0.2 \mathrm{~A}\).

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