Question

The hydrocarbon, pentane, C₅H₁₂, reacts with oxygen to form carbon dioxide and water. In a 3.00 L container at 25 ºC are placed 0.520 moles of O₂ gas and 0.400 moles of solid C₅H₁₂.

b) How many moles of CO₂(g) is produced?

Answer 1

Balanced chemical equation is:

C5H12 + 8 O2 ---> 5 CO2 + 6 H2O

1 mol of C5H12 reacts with 8 mol of O2

for 0.4 mol of C5H12, 3.2 mol of O2 is required

But we have 0.52 mol of O2

so, O2 is limiting reagent

we will use O2 in further calculation

According to balanced equation

mol of CO2 formed = (5/8)* moles of O2

= (5/8)*0.52

= 0.325 mol

Answer: 0.325 mol