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Consider the titration of 100.0 ml of 0.200 M CH3NH2 by 0.100 M HCl. (Kb for...

Consider the titration of 100.0 ml of 0.200 M CH3NH2 by 0.100 M HCl. (Kb for CH3NH2 = 4.4 x 10^-4) At what volume of HCl added, does the pH = 10.64?

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Answer #1

Pkb=-leg kb = -kg(4-4x154)=-beg 4444 legio=-0-64+4x4 = 3.36 Toode . Centerstate of CH3CH2Nb=0-200M = 0-200 mille volume ChaChT IPOH= 3.36+ log CH3CHNBCE)=33+1 0-12 mil 7 O T CHECHENHET 10:62-(-12) hoff 14.00-PH= 3.36+674-_ \ 14.00-10.64-3-36= log coo20N 0.12 0.02-04 7 0.02-0-12 = 6-12 OLX+0.1% = 0.02 => 0-22 = 0.02= x= 3:02=0-1 volone Of Hel Schusterna adiled = 0:1L = 100m

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