Using the equations 2Sr(s)+O2(g) → 2 SrO (s) ΔH° = -1184 kJ/mol

Question

Question

Using the equations

2Sr(s)+O₂(g) → 2 SrO (s) ΔH° = -1184 kJ/mol

SrO (s) +CO₂ (g) → SrCO₃ (s) ΔH° = -234 kJ/mol

CO₂ (g) → C(s) +O2 (g) ΔH°= 394 kJ/mol

Determine the enthalpy for the reaction

2 SrCO₃ (s) → 2 Sr (s)+2 C(s)+ 3O₂ (g). kJ/mol

science chemistry

Answer 1

Answer #1

in scientific notation answer is 2.440 x 10³

Answer 2

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