Calculate the concentration of all species in a 0.12 M KF solution. Ka(HF)=6.3×10−4 [ K +...

Question

Question

Calculate the concentration of all species in a 0.12 M KF solution.
Ka(HF)=6.3×10−4

[ K + ], [F−], [HF], [OH−], [H3O+] =

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Answer 1

Answer #1

[kt] =0.12 m. Now, the F- ion acts as a base by the equation F+H20 HFTOH Kb for this is given by: Ky=[HF] [DM] /[F] The value

Answer 2

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