Question

For each of the reactions, calculate the mass (in grams) of the duct that forms when 3.67 g of the underlined reactant completely reacts. Assume that there is more than enough of the other react

Answer 1

a) Ba + Cl2 --------> BaCl2
3.67g/137.3g/mol xs 0 initial moles
0 xs 3.67/137.3 moles after rxn
Thus mass of BaCl2 = moles x molar mass
= 3.67/137.3 molx 208.3g/mol
=5.57 g
b) CaO + CO2 ---------> CaCO3
3.67g/ 56g/mol xs 0 initial mol
0 xs 3.67g/ 56g/mol
mass of CaCO3 formed = 3.67g/ 56g/mol x100g/mol
= 6.55 g
c) 2Mg +O2 ---------> 2 MgO
3.67g/24g/mol xs 0 initial moles
0 - 3.67g/24g/mol after rxn
mass of MgO formed = 3.67g/24g/mol x40g/mol
=6.12 g
d)4Al +3O2 ---------------> 2Al2O3
3.67/27mol xs 0 initial moles
0 xs (1/2 )x3.67/27mol
mass of AL2O3 formed = (1/2 )x3.67/27mol x 102g/mol
= 6.93 g