For the reaction 2N2H4 (l) + N2O4 (l) → 3N2 (g) + 4H2O(l), determine the mass...
For the reaction 2N2H4 (l) + N2O4 (l) → 3N2 (g) + 4H2O(l),
determine the mass of H2O formed when 20.0 grams of N2O4 react.
A) 3.6 grams B) 7.8 grams C) 8.6 grams D) 15.6 grams
Homework Answers
The given balanced equation ::
2N2H4 + N2O4 ---> 3N2 + 4H2O (l)
equation says 1 mole N2O4 generates 4 mole water
given
maas of N2O4 = 20.g
molar mass of N2O4 = [2*14.01 + 4*16] g/mol = 92.01 g/mol
# moles N2O4 present = 20 g/92.01 g/mol =0.2174 mols
mole ratio N2O4:H2O = 1:4
so 0.2174 mols N2O4 generates 4*0.2174 mols H2O
=0.8696 mols
Thus mass of H2O formed= moles of H2O present xmolar mass of
H2O
=0.8696 mols*18.015 g/mol = 15.6 g
Answer option D
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