1.For the reaction at equilibrium 2 SO3↔ 2 SO2 + O2 (∆Horxn= 198 kJ/mol), if we increase the reaction temperature, the equilibrium will (1 point ) *
No shift
None of the above
Question lacks sufficient information
Shift to the right
2.
For the equilibrium reaction 2 SO2(g) + O2(g) ↔ 2 SO3(g), ∆Horxn = -198 kJ/mol. Which one of these factors would cause the equilibrium constant to increase? (1 point ) *
Add a catalyst
Decrease the temperature
None of the above
Remove O2 gas


1.For the reaction at equilibrium 2 SO3↔ 2 SO2 + O2 (∆Horxn= 198 kJ/mol), if we...
For the equilibrium reaction 2SO2(g) + O2(g) 2SO3(g), delta Hrxn = -198 kJ/mol. Which one of these factors would cause the equilibrium constent to increases? Decrease the temperature. Add SO2 gas Remove O2 gas Add a catalyst. None of these Consider this reaction at equilibrium If the volume of the system is compressed at constent temperature, what change will occure in the position of the equilibrium?
Consider the following equilibrium reaction : Heat + 2 SO2 (g) + O2(g) ↔ 2 SO3(g) Assume the above reaction is allowed to reach equilibrium prior to the following changes. Answer the following questions by writing increase, decrease or remain the same on the line. **please also explain why** If the reaction mixture is heated up , the value of the equilibrium constant will _______________________ If SO2 (g) is added to the reaction vessel the concentration of O2(g) will____________________________. If SO3 (g) is...
3. For the reaction : 2 SO2 (g) + O2 (g) ↔ 2 SO3 (g) the value of K is 17.3 at 38 C If the equilibrium concentration of sulfur dioxide at 38 C is found to be 0.126 M, and the equilibrium concentration of oxygen is found to be 0.0582 M, what is the equilibrium concentration of sulfur trioxide?
The reaction 2 SO2 + O2 = 2 SO3 is exothermic. Which of the following would be true for a person wanting to force the equilibrium to the right? a. They should (increase/decrease) the reaction temperature b. They should (increase/decrease) the total pressure c. they should (add/remove) SO2 d. they should (add/remove) O2 e. they should (add/remove) SO3 why?
Consider the following system at equilibrium where Kc = 34.5 and H° = -198 kJ/mol at 1150 K. 2 SO2 (g) + O2 (g) 2 SO3 (g) The production of SO3 (g) is favored by: Indicate True (T) or False (F) for each of the following: 1. decreasing the temperature. 2. decreasing the pressure (by changing the volume). 3. decreasing the volume. 4. removing SO3 . 5. adding O2 .
1. Predict the effect on the equilibrium system in below if the reaction temperature is increased. 2 SO2(g) + O2(g) ↔ 2 SO3(g)+ heat a. Shift to the product side b. There will be no change. c. Shift to the reactant side 2. Predict the effect on the equilibrium system in below if the SO2 gas concentration is decreased. 2 SO2(g) + O2(g) ↔ 2 SO3(g) a. Shift to product side b. shift to reactant side c. no change 3....
3. For the reaction : 2 SO2 (g) + O2 (g) ↔ 2 SO3 (g) A. If the value of K is 17.3 at 38 C, what is the value of K for the reverse reaction at 38 C?
5) For the reaction 2 SO2(g) + O2(g) → 2 SO3(g), if initially P(SO2) = 1.2 atm, P(O2) = 1.8 atm, and P(SO3) = 2.1 atm, calculate AG for this reaction at 25°C. The following data is valid at 25°C: AG° (kJ/mol) SO 300.4 SO3 370.4 A) -140.0 kJ/mol B)-141.3 kJ/mol C)-138.7 kJ/mol D) 1,174.7 kJ/mol E) -137.6 kJ/mol
For the following endothermic reaction system at equilibrium: 2SO3(g) <---> 2SO2(g) + O2(g) Choose the changes that will shift the equilibrium position to the right. (Select all that apply.) Add Ne(g) Add SO2(g) Remove SO3(g) Decrease temperature Add a catalyst Increase temperature Decrease volume
1. Consider the following system at equilibrium where H° = -198 kJ/mol, and Kc = 34.5 , at 1150 K. 2 SO2(g) + O2(g) 2 SO3(g). When 0.11 moles of SO3(g) are added to the equilibrium system at constant temperature:The value of Kc Increases, Decreases, remains the same The value of Qc is greater than, is equal to, is less than kc. The reaction must run in the forward direction to restablish equilibrium. run in the reverse direction to restablish equilibrium....