Question

Solid nickel reacts with aqueous lead(II) chloride in a single displacement reaction.

Write and balance the above reaction. Showing the oxidation number method, determine the following:

Species getting oxidized:_________

Species getting reduced:_________

Oxidizing agent: ____________

Reducing agent:_________

Can you add the full work so I can study it please

Answer 1

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Answer Solid Nickel reacts with aqueous lead (11) chloride in Single displacement reaction chemical equation; (Balanced) Nics) + PbCl2 (aq) Nick Caq) + Pb (s) d ON = +2 ON = of Ni Ръ where, ON = oxidation number, ON=0 ON 2+2 of Pb of Ni 0 species getting Oxidized; species getting oxidized are theuse species whose Oridertion number is increased in product. Here, Nics) whose oxidation number is o in reactant side but Ni oxidation number in Nicla is t2 in product side. Therefore, Nics) species getting oscidized getting reduced: species getting reduced are those species whose oxidation number is decreased in product. Csgerey withoxidation number of pb in Polly is +2 in (11) species

reactant side but po oxidation number in Pb (s) is Olzero) in product side. Therefore, Polly species getting reduced cii) Oxidizing agenti An oxidizing agent is a species that oxidize other species. it means, oodation number of oxidizing agent is decreased in product. Here: Polla is oxidizing agent because oxidation number of Pb in Alla in reactant side is +2 and oxidation number of Pb in Pb(s) in product side is o. it mean oxidation number e, eb \% са схео4ed. V) Reducing agent : A Reducing agent is a species that reduce other species. It means, oxidation number of reducing agent is increased in product, Here Ni (s) is reducing agent because oxidation number of Ni in nics) is 0 (zero) In reactant side and oxidation member of Ni in Nicla in product side is t2. it means oxidation number of Ni is increased. Scanned with CamScanner