Question

Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions. H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e− 12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g) Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e− 2NiO(OH)(s)+2H2O(l)+2e

Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions.

H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e−

12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g)

Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−

2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq)2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq)

Fe(s)⟶Fe2+(aq)+2e−Fe(s)⟶Fe2+(aq)+2e−

oxidation

reduction

reduction

oxidation

reduction

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Answer #1

H2(g) ---> 2H+ + 2e-

This is an oxidation half reaction as here electrons are being released in the reaction.

O2 + 2H+ + 2e- --> H2O

This is a reduction half reaction as here electrons are being consumed in the product formation.

Cd(s) + 2OH-(aq) --> Cd(OH)2 +2e-

This is an oxidation half reaction as here electrons are released in the product formation.

2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq)

This is a reduction half reaction as here electrons are being consumed in the product formation.

Fe(s)⟶Fe2+(aq)+2e−

This is an oxidation half reaction as here electrons are being released in the product formation.

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Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions. H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e− 12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g) Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e− 2NiO(OH)(s)+2H2O(l)+2e
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