Question

The combustion of propane, C3H8, occurs via the reaction C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) with heat of formation values given...

The combustion of propane, C3H8, occurs via the reaction C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) with heat of formation values given by the following table:

Substance ΔH∘f (kJ/mol)

C3H8 (g)=  -104.7

CO2(g)= −393.5

H2O(g)= −241.8

Calculate the enthalpy for the combustion of 1 mole of propane.

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Answer #1

C₂H8 (9) +502 (8) - 3 Colgt AH (9) Ale (reaction) = { AM (proderets) - LAHp (creactants) AH & (C₂H8 ) = - 104.7 kJ/mol DH (CO

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