Question

Find the pH of each of the following solutions of mixtures of acids.

8.0×10−2 M in HNO3 and 0.165 M in HC7H5O2,

1.5×10−2 M in HBr and 2.0×10−2 M in HClO4,

9.5×10−2 M in HF and 0.230 M in HC6H5O,

0.110 M in formic acid and 4.5×10−2 M in hypochlorous acid

PLEASE show work

Answer 1

2 HNO3 + C7 H602 HNO is strong acid and it completly dissocrated but Bentoic and (ca Ho O2) is wear and and if ka value is 6.3X105 [HNOz] - [ht] = 8.0x10² M = 0.08M Por Bentoic and of cool cooth HP kes [Colts coron] LHA 14 [cets Coolt 6.34105 [A+] [16] [cent Cool - 0.165 [H+] 6.34105 x 0.165 = 1.039x105. [147] - J 1. OBgX05 - 3. 224 x 103 = 0.0032 20 M . Total [14+] = 0.08+ 0.0032 0.0832 M 2. PH ₂ lag [101] = -loy (0.0 832) = 1.08

Her an HBr and Helly both are strong an Снан) - Уход Енесу : [не.0 хон. Total [HT] = 1.5* X10 2 + 2,0 810 3.5810 2M PH2 - log [41) = -long (3.5x102) = 1.6 093) Borostymul an s tikkek TCC) Hf and its of both one weak kaff to = 6.68104 Ka A for Colt Olt - 1.881010 I HF & H + + po Ka (HP) [HT] [F]. Ildf) p 6.60104 - [41] PE 9. 2 : [141] 26.6x10 " x 9.5x18 ² = 6, 27x105 [lt t] √6.27X105 a 7.92X103

Ets of 150 res ker (calits on) [Colgo ] [H] 1.8x1010 [wn Colts op] 0.230 [18+] = 1.1810 10 x 0.230 - 2.581810 [H . 26581x10-1 - 5.08x106 Totail [141] = 7.92x10 3 5,088106 = 7.925 810-3 PH = -loy [4+] = -log (7.925x103) = 2.10 liv Both formic and and hypochlorus and are weak and.. Kaoz formic and = 1.88104 Ka of Hypochlorous and = 3.0x108. [Heaost] = 0.10M : [Helo] = 4.5x102M. HCooH & H t + coor [н'][Не се) [1] [HCcod ] [COoH] 1.88104 = [lator Orll [ht] = 0.1 x 1.8x104 = 1.98810 [ht] = V1.988105 = 4.45X10 3 M Helo H+ + co- Kac [lt + ] [clo ] [14+] [Hero] [Helor 3.0x108 - [H +7 4.58102 [HT] = 3.0x108 x 4.5X102 - 10358109 [HP] =√1.354189 = 3.67x105m

Total [HT] = 4.45810 3 + 3.67x10-5 = 4.4878103 M. ...PH = -log [HD] - log (4.487 X10 3] PH= 2.35