For the reaction H2(g)+I2(g)⇌2HI(g), K= 57.0 at 700 K what can be said about this reaction at this temperature? For the reaction , at 700 what can be said about this reaction at this temperature? The equilibrium lies far to the right. The reaction will proceed very slowly. The reaction contains significant amounts of products and reactants at equilibrium. The equilibrium lies far to the left.

For the reaction H2(g)+I2(g)⇌2HI(g), K= 57.0 at 700 K what can be said about this reaction...
The equilibrium constant for the reaction: H2(g) + I2(g) <--> 2HI(g) is 54 at 700 K. A mixture of H2, I2 and HI, each at 0.020 M, was introduced into a container at 700 K. Which of the following is true? At equilibrium, [H2] = [I2] = [HI]. No net change occurs because the system is at equilibrium. The reaction proceeds to the left producing more H2(g) and I2(g). The reaction proceeds to the right producing more HI(g). At equilibrium,...
Calculate the equilibrium concentrations of H2, I2, and HI at 700 K if the initial concentrations are [H2] = 0.200 M and [I2] = 0.400 M. The equilibrium constant Kc for the reaction following reaction is 57.0 at 700 K. (Show Work) H2(g)+I2(g)<--- ---->2HI(g)
Consider the following reaction: H2(g)+I2(g)⇌2HI(g) A reaction mixture in a 3.70 L flask at a certain temperature initially contains 0.766 g H2 and 97.0 g I2 At equilibrium, the flask contains 90.2 g HI. Calculate the equilibrium constant (Kc) for the reaction at this temperature. I keep getting 700 as the answer but it's not right.
For the reaction H2(g)+I2(g)⇌2HI(g), Kc= 55.3 at 700 K. In a 2.00-L flask containing an equilibrium mixture of the three gases, there are 0.053 g H2 and 4.38 g I2. What is the mass of HI in the flask? Express your answer to two significant figures and include the appropriate units.
Consider the reaction: H2(g)+I2(g)⇌2HI(g) A reaction mixture in a 3.69 −L flask at 500 K initially contains 0.377 g H2 and 17.93 g I2. At equilibrium, the flask contains 17.72 g HI. Calculate the equilibrium constant at this temperature.
H2(g)+I2(g)⇌2HI(g) For the above reaction, Kc=55.3 at 700 K. In a 2.00-L flask containing an equilibrium mixture of the three gases, there are 0.053 g of H2 and 4.39 g of I2. What is the mass of HI in the flask?
Consider this reaction: H 2 (g)+ I 2 (g)⇌2HI(g) H2(g)+I2(g)⇌2HI(g) A rxn mixture in a 3.73 L flask at a certain temperature initially contains 0.766 g H2 and 96.7 g I 2 I2 . At equilibrium, the flask holds 90.3 g HI . Calculate the equilibrium constant (Kc)(Kc) for the reaction at this temperature. Record your answer using two significant figures.
. Consider the reaction: H2(g) + I2(g) ? 2HI(g) A reaction mixture at equilibrium at 175 K contains PH2 = 0.958 , PI2 = 0.877 , and PHI= 0.020 . A second mixture not equilibrium, but at the same temperature,contains PH2 = PI2 = 0.621 , and PHI = 0.101 . a) For the second mixture, calculate Q. b) Determine whether the reaction in the second mixture will shift right or shift left.c) Construct an ICE table. Keep in mind your...
The equilibrium constant K for the reaction H2(g) + I2(g) 2HI(g) is 51 at 300oC. A 2 L flask was filled with 1 mol H2 and 1 mol I2 at 300oC and the reaction was allowed to come to equilibrium. (i) Calculate the equilibrium concentrations of all three species. If this reaction was performed with the same quantities but at a higher pressure what would be the effect on the position of equilibrium? (ii) If an equilibrium reaction as drawn...
the following statements relate to the reaction for the formation of HI: H2(g) + I2(g)--> 2HI(g) Rate= k[H2][I2] Determine which of the following statements is true. (a) The reaction must occur in a single step (b) This is a second-order reaction overall (c) If the concentrations of both reactants are doubled, the rate will double (d) Raising the temperature lowers the activation energy for this reaction