the combustion of pentane produces heat according to theequation: C5H12(l) + 8O2(g) -->5CO2(g) + 6H2O(l) &nb...
Homework Answers
44*5=220 g CO2 ==> 3510 kJ heat [Because molecularweight of CO2 is 44, which means each mol CO2 weighs 44 g]
1 kJ heat==> 220/3510 g CO2 = 0.06267 gCO2
2500 kJ heat==> 0.06267 * 2500 g CO2 =156.67 gCO2
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the combustion of pentane produces heat according to
theequation:
C5H12(l) + 8O2(g)
-->5CO2(g) +
6H2O(l) &nb...
The combustion of pentane, C5H12, occurs via the reaction C5H12(g)+8O2(g)→5CO2(g)+6H2O(g) with heat of formation values given...
The combustion of pentane, C5H12, occurs via the reaction C5H12(g)+8O2(g)→5CO2(g)+6H2O(g) with heat of formation values given by the following table: Substance ΔH∘f (kJ/mol) C5H12 (g) -119.9 CO2(g) −393.5 H2O(g) −241.8 Calculate the enthalpy for the combustion of 1 mole of pentane. Express your answer to four significant figures and include the appropriate units.
Calculate ΔHrxn for the following reaction: 5C(s)+6H2(g)→C5H12(l) Use the following reactions and given ΔH values: C5H12(l)+8O2(g)→5CO2(g)+6H2O(g),...
Calculate ΔHrxn for the following reaction: 5C(s)+6H2(g)→C5H12(l) Use the following reactions and given ΔH values: C5H12(l)+8O2(g)→5CO2(g)+6H2O(g), ΔH= -3244.8 kJ C(s)+O2(g)→CO2(g), ΔH= -393.5 kJ 2H2(g)+O2(g)→2H2O(g), ΔH= -483.5 kJ
Pentane (C5H12) burns in oxygen to produce carbon dioxide and water via the following reaction: C5H12(g)+8O2(g))...
Pentane (C5H12) burns in oxygen to produce carbon dioxide and water via the following reaction: C5H12(g)+8O2(g)) Δ⟶ 5CO2(g)+6H2O(g) Calculate the mass of CO2 that can be produced if the reaction of 36.5 g of pentane and sufficient oxygen has a 65.0 % yield.
Calculate ΔHrxn for the following reaction: 5C(s)+6H2(g)→C5H12(l) Use the following reactions and given ΔH values: C5H12(l)+8O2(g)→5CO2(g)+6H2O(g),ΔHC(s)+O2(g)→CO2(g),ΔH2H2(g)+O2(g)→2H2O(g),ΔH===−3244.8kJ−393.5kJ−483.5kJ...
Calculate ΔHrxn for the following reaction: 5C(s)+6H2(g)→C5H12(l) Use the following reactions and given ΔH values: C5H12(l)+8O2(g)→5CO2(g)+6H2O(g),ΔHC(s)+O2(g)→CO2(g),ΔH2H2(g)+O2(g)→2H2O(g),ΔH===−3244.8kJ−393.5kJ−483.5kJ Express your answer to four significant figures in kilojoules.
Calculate ΔHrxn for the following reaction: 5C(s)+6H2(g)→C5H12(l) Use the following reactions and given ΔH′s. C5H12(l...
Calculate ΔHrxn for the following reaction: 5C(s)+6H2(g)→C5H12(l) Use the following reactions and given ΔH′s. C5H12(l)+8O2(g)→5CO2(g)+6H2O(g), ΔH= -3244.8 kJ C(s)+O2(g)→CO2(g), ΔH= -393.5 kJ 2H2(g)+O2(g)→2H2O(g), ΔH= -483.5 kJ Express your answer to for significant figures.
If 6.92 mol of C5H12 reacts with excess O2, how many moles of CO2 will be...
If 6.92 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction? C5H12+8O2⟶6H2O+5CO2 moles of CO2: mol
1) .C5H12+8O2→5CO2+6H2O What is the oxidizing agent? C ,O , O2, C5H12 2)In the following reaction,...
1) .C5H12+8O2→5CO2+6H2O What is the oxidizing agent? C ,O , O2, C5H12 2)In the following reaction, what is the reducing agent? N2+2 O2→2 NO2 NO2, O2, N2 3)Consider the reaction: MnO−4(aq)+I−(aq)→Mn2+(aq)+I2(s) How many electrons are transferred in this reaction? 0 2 5 7 10
If pentane, C5H12, reacts with excess oxygen according to CsH12 + O2 +5CO2+ H20 how many...
If pentane, C5H12, reacts with excess oxygen according to CsH12 + O2 +5CO2+ H20 how many grams of pentane are needed to produce 7.89 x 1023 molecu (Enter your answer to the hundredth place.)
If 8.58 moles of C5H12 reacts with excess O2, how many moles of CO2 will be...
If 8.58 moles of C5H12 reacts with excess O2, how many moles of CO2 will be produced in the following combustion reaction? C5H12 + 8O2 ----> 6H2O + 5CO2 Please explain how answer is found if possible.
Calculate delta Hrxn for the following reaction: 5C(s)+6H2(g)--->C5H12(l) use the following reactions and given d...
Calculate delta Hrxn for the following reaction: 5C(s)+6H2(g)--->C5H12(l) use the following reactions and given delta H's: C5H12(l)+8O2(g)---> 5CO2(g)+6H2O(g) delta H= -3505.8 kJ C(s)+O2(g)--->CO2(g) delta H= -393.5 kJ 2H2(g)+O2(g)---> 2H2O(g) delta H= -483.5 kJ The steps to solving this problem would be greatly appreciated! Thanks so much!
If pentane, C5H12, reacts with excess oxygen according to CsH12 + O2 +5CO2+ H20 how many grams of pentane are needed to produce 7.89 x 1023 molecu (Enter your answer to the hundredth place.)
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