Calculate the standard entropy of reaction at 25 ?C for the
decomposition of calcium carbonate:
CaCO3(s)?CaO(s)+CO2(g)
The entropy of the reaction is given as
Entropy (rxn) = Entropy(Products) - Entropy(reactants)
Entropy(Products) = Entropy(CaO) + Entropy(CO2)
=> 39.7 + 213.6 [data taken from net]
=> 253.3 J/K mol
Entropy (Reactants) = Entropy(CaCO3)
=>92.9 J/K mol
Net Entropy of Reaction = 253.3 - 92.9 = 160.4 J/K mol
Calculate the standard entropy of reaction at 25 ?C for the decomposition of calcium carbonate: CaCO3(s)?CaO(s)+CO2(g)...
The decomposition of calcium carbonate is given by the equation, CaCO3(s) →CaO(s) + CO2(g). Determine if the reaction is spontaneous at room temperature, given the following thermodynamics parameters: Δ? = 178 kJ/mol Δ? = 163 J/Kmol
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Calculate the standard enthalpy of formation of solid calcium
carbonate (CaCO3) using the following thermochemical
information:
Calculate the standard enthalpy of formation of solid calcium carbonate (CaCo3) using the following thermochemical information: 2 Cao(s) 2 Ca(s) O2(g) AH 1270.2 kJ C(s) O2 (g) CO2 (g) AH 393.5 kJ AH 178.3 kJ CaO(s) CO2 (g) CaCO3(s) kJ AH
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Consider the following reaction: CaO (s) + CO2 (g) → CaCO3 (g) If 12.9 g of carbon dioxide, CO2, react, how many grams of calcium carbonate, CaCO3, are produced?
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