Question

Use the Data table to calculate ∆H for the reaction below:

Use the Data table to calculate ∆H for the reaction below:

Reactions:                                                                            Change in Enthalpy (∆H)

(1)    C (s) + O2 (g) -> CO2(g)                                                     ∆H1 = -393.5 kJ/ mol

(2)    H2 (g) + 1/2 O2 (g) -> H2O (l)                                                ∆H2 = -285.8 kJ/mol

(3)    2C2H6 (g) + 7O2 (g) -> 4 CO2 (g) + 6 H2O (l)                          ∆H3 = -283.0 kJ/mol

Calculate the enthalpy change for the reaction:

2 C (s) + 3 H2 (g) -> C2H6(g)                                                     ∆H = ______________kJ/mol

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
Use the Data table to calculate ∆H for the reaction below:
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below:...

    6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol

  • 6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below:...

    6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol

  • The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) +...

    The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) + 3 H2O(l) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1):     C(s) + O2(g) → CO2(g)     ΔH = −393.5 kJ/mol reaction (2):     H2(g) + 1/2 O2(g) → H2O(l)     ΔH = −285.8 kJ/mol reaction (3):     2 C(s) + 3 H2(g) → C2H6(g)     ΔH = −84.0 kJ/mol

  • From the following data, C(graphite) + O2(g) → CO2(g) AHrxn = -393.5 kJ/mol H2(g) + O2(g)...

    From the following data, C(graphite) + O2(g) → CO2(g) AHrxn = -393.5 kJ/mol H2(g) + O2(g) → H200) AH"rxn = -285.8 kJ/mol 2C2H6(g) + 702(g) -> 4CO2(g) + 6H2O(l) Arxn=-3119.6 kJ/mol Calculate the enthalpy change for the reaction: 2 C(graphite) + 3H2(g) + C2H668)

  • Determine Heat of reaction (Hrxn) for: 2 C (s, graphite) + 3 H2 (g) ------> C2H6...

    Determine Heat of reaction (Hrxn) for: 2 C (s, graphite) + 3 H2 (g) ------> C2H6 (g) from the following C (s, graphite) + O2 (g) ------> CO2 (g) delta H = -393.5 kJ H2 (g) + 1/2 O2 (g) ------> H2O (l) delta H = -285.8 kJ 2 C2H6 (g) + 7 O2 (g) ------> 6 H2O (l) + 4 CO2 (g) delta H = -3,119.6 kJ

  • calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l)

    calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l) Given the reactions N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol H2(g) + O2(g) -> H2O2(l) enthalpy of H = -187.8 kJ

  • Consider the exothermic reaction 2C2H6(g)+7O2(g)→4CO2(g)+6H2O(g) Calculate the standard heat of reaction, or ΔH∘rxn, for this reaction...

    Consider the exothermic reaction 2C2H6(g)+7O2(g)→4CO2(g)+6H2O(g) Calculate the standard heat of reaction, or ΔH∘rxn, for this reaction using the given data. Also consider that the standard enthalpy of the formation of elements in their pure form is considered to be zero. Reactant or product ΔH∘f (kJ/mol) C2H6(g) -84.7 CO2(g) -393.5 H2O(g) -241.8 Express your answer to four significant figures and include the appropriate units.

  • 1. Using the reactions given below please calculate the change in enthalpy (delta H) for the...

    1. Using the reactions given below please calculate the change in enthalpy (delta H) for the stated reaction. Stated Reaction: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) delta H = ?! Given Reactions & Enthalpy Changes: 2 Fe(s) + 3/2 02(g) → Fe2O3(s) 2 Fels) * delta H = -824.2 kJ delta H = -282.7 kJ CO(g) + 4 02(g) → CO2(g) 2. Using the reactions given below please calculate the change in enthalpy (delta H) for...

  • please explain each step in clear writing. Chloroform (CHCI3) is formed from methane and chlorine in...

    please explain each step in clear writing. Chloroform (CHCI3) is formed from methane and chlorine in the following reaction: CH4 (g)3C12 (g)3HC1(g)+CHCI3 (g) Calculate A, Ho, the enthalpy change for this reaction, using the standard molar enthalpy change of formation of CHCI3 (g), AfH° = -103.1 kJ mol1, and the standard enthalpy changes for the following reactions: CH4 (g)202 (g)2H2O (e) CO2 (g) AH°=-890.4 kJ mol-1 2HC1(g) H2 (g)Cl2 (g) A,.H +184.6 kJ mol1 C(graphite)O2 (g)CO2 (g) A H°=-393.5 kJ...

  • Calculate the standard enthalpy change for the fermentation process, in which glucose (C6H12O6) is converted into...

    Calculate the standard enthalpy change for the fermentation process, in which glucose (C6H12O6) is converted into ethanol (C2H5OH) and carbon dioxide (CO2). Substance Enthalpy of Formation, Δ H o f CO2 (g) −393.5 kJ/mol CO2 (aq) −412.9 kJ/mol C2H5OH (l) −276.98 kJ/mol C6H12O6 (s) −1,274.5 kJ/mol H2O (g) −241.8 kJ/mol H2O (l) −285.8 kJ/mol O2 (g) 0 kJ/mol

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT