Question

****python****

Q1.

Write a recursive function that returns the sum of all numbers up to and including the given value.

This function has to be recursive; you may not use loops!

For example:

Test	Result
print('%d : %d' % (5, sum_up_to(5)))	5 : 15

Q2,

Write a recursive function that counts the number of odd integers in a given list.

This function has to be recursive; you may not use loops!

For example:

Test	Result
print('%s : %d' % ([2, 3, 5, 6], count_odd([2, 3, 5, 6])))	[2, 3, 5, 6] : 2

Q3.

Write a recursive Python function, given a non-negative integer N, to calculate and return the sum of its digits.

Hint: Mod (%) by 10 gives you the rightmost digit (126 % 10 is 6), while doing integer division by 10 removes the rightmost digit (126 / 10 is 12).

This function has to be recursive; you may not use loops! This function takes in one integer and returns one integer.

For example:

Test	Result
print(234, ":", sum_digits(234))	234 : 9

Q4.

Write a recursive function to compute the following series:

This function has to be recursive; you may not use loops!

For example:

Test	Result
print('%d : %.6f' %( 2, m(2)))	2 : 1.500000

Thank you!

Answer 1

Dear Student ,

As per the requirement submitted above , kindly find the below solution.

Question 1:

#function that return sum
def sum_up_to(num):
#checking number
if(num<=1):
#if number equal to 1 then
return num
else:
#recursively call the function
return num+sum_up_to(num-1)
  
#call function
print('%d : %d' % (5, sum_up_to(5)))

======================================================

Output : Compile and Run above function to get the screen as shown below

Screen 1 :main.py

main.py 1 #function that return sum 2 def sum_up__to(num): #checking number if (num-1): #if number equal to 1 then return num else: 7 #recursively call the function return num+sum_up_to(num-1) 10 11 #call function 12 print('%d %d' % ( 5, sum_up_to(5))) input 5 15 , Program finished with exit code 0 Press ENTER to exit console.

*************************

Question 3:

#function to find out sum of digits
def sum_digits(num):
#checking number
if num==0:
#if num is equal to zero
return 0
else:
#call recursively sum_digits
return num%10+sum_digits(num//10)
#function call
print(234, ":", sum_digits(234))

===================================

Output :

main.py 1 #function to find out sum of digits 2 def sum_digits(num): #checking number if num--0: 4 #if num is equal to zero 5 return e else: 7 #call recursively sum digits return num 10+sum_digits(num//10) 10 #function call 11 print (234, sum digits(234)| input 234 9 . . Program fini shed with exit code o Press ENTER to exit console. Ln oN

NOTE : PLEASE FEEL FREE TO PROVIDE FEEDBACK ABOUT THE SOLUTION.