Question

Write a program that reads integers, finds the smallest of them, and counts its occurrences. Assume that the input ends with number -1. Suppose that you entered 4 2 9 2 2 -1; the program finds that the smallest is 2 and the occurrence count for 2 is 3. (Hint: Maintain two variables, min and count. min stores the current min number, and count stores its occurrences. Initially, assign the first number to min and 1 to count. Compare each subsequent number with min. If the number is smaller than min, assign it to min and reset count to 1. If the number is equal to min, increment count by 1.)

Answer 1

ANSWER:-

#include <iostream>

using namespace std;

int main() {

int num,min,count=0;

cout<<"enter a number : ";

cin>>num;

min=num;

while(num!=-1)

{

if(min==num)

count++;

if(min>num)

{

min=num;

count=1;

}

cin>>num;

}

cout<<"smallest number : "<<min<<endl;

cout<<"occurence of smallest number : "<<count;

return 0;

}

// OUTPUT

// if any doubt please comment