Question

3.22 LAB: Remove gray from RGB Summary: Given integer values for red, green, and blue, subtract...

3.22 LAB: Remove gray from RGB

Summary: Given integer values for red, green, and blue, subtract the gray from each value.

Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray).

Given values for red, green, and blue, remove the gray part.

Ex: If the input is:

130 50 130

the output is:

80 0 80

Find the smallest value, and then subtract it from all three values, thus removing the gray.

#include <iostream>
using namespace std;

int main() {

   /* Type your code here. */

   return 0;
}

0 0
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Answer #1
#include<iostream>
using namespace std;
int main()
{
   int r,g,b;
   
   cin>>r>>g>>b;
   
   int min = r;
   if(min > g){
          min = g;
   }   
   if(min > b){
          min = b;
   }
   cout<<(r-min)<<" "<<(g-min)<<" "<<(b-min)<<endl;
   return 0;
}
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Answer #2

PYTHON


red_amount = int(input())

green_amount = int(input())

blue_amount = int(input())


min_value = red_amount


if green_amount < min_value:

    min_value = green_amount


if blue_amount < min_value:

    min_value = blue_amount

    

red_amount = red_amount - min_value

green_amount = green_amount - min_value

blue_amount = blue_amount - min_value


print(red_amount, green_amount, blue_amount)


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