Question

write a program that read the integers between 1 and 100 and count the occurrence of each number. Assume the input end with 0. here is samole of the program:

Enter the integers between 1 and 100: 2 5 6 5 4 3 23 43 2 0 Enter
2 occurs 2 times
3 occurs 1 time
4 occurs 1 time
5 occurs 2 times
6 occurs 1 time
23 occurs 1 time
43 occurs 1 time

> doesn't work

Answer 1

Program plan:

• In the main() function,

o Read the number of integers between 1 and 100.

o Use for loop to initialize the value of each array element.

o Use the while loop to read the numbers and stop reading the number until the user enters the number 0.

o Use for loop to read the number of integers.

• Next, compare whether the entered element is greater than 0.

• If yes, at sequence loop execution check whether the current element is repeated again. If condition is true, then update the count of current element.

• Finally, return and display the count of occurrences of a given number.

Program:

/**********************************************************

* Program demonstrates count the occurrence of numbers *

**********************************************************/

This program demonstrates to calculate the count of occurrences of numbers.

// Header file section

#include

using namespace std;

The function main() is a predefined function. It uses loop statement to get the number of integers from the user, and to count the occurrence of the numbers.

// Main function definition

int main()

{

//Declare the variables

int array[100];

int numbers;

cout<<"\nCount the occurrence of numbers:\n";

Read the input values for ‘numbers’.

//Get the input from user

cout<<"\nEnter the integers between 1 and 100 (Enter '0' to stop):\n";

Execute the for loop until it exceeds 100 numbers and then it initializes the value of each array element.

/* Loop used to initialize values for all array elements */

for (int i = 0; i < 100; i++)

{

// Initialize the value of array

array[i] = 0;

}

Use the while loop to read the numbers and exit the loop until the user enters the value 0.

// Read the numbers

cin >> numbers;

/* Execute the while loop until the number is not

equal to 0*/

while (numbers != 0)

{

array[numbers - 1]++;

cin >> numbers;

}

Execute for loop until the j variable is less than 100.

/* Execute the for loop until the condition leads to false.*/

for (int j = 1; j < 100; j++)

{

Ensure whether the array element is greater than 0.

/* Check whether the array variable contains an element greater than 0 */

if (array[j] > 0)

{

Calculate and display the count of occurrences of a given number.

/*Count and display the occurences of a

number*/

cout << (j + 1) << " occurs " << array[j] <<

((array[j] == 1) ? " time" : " times") << endl;

}

}

//Pause the input screen

system ("pause");

//Return the value

return 0;

}

Sample Output:

Count the occurrence of numbers:

Enter the integers between 1 and 100 (Enter '0' to stop):

78

23

45

65

56

23

0

23 occurs 2 times

45 occurs 1 time

56 occurs 1 time

65 occurs 1 time

78 occurs 1 time