A projectile is fired with an initial speed of 36.2m/s at an angle of 41.1 degrees above the horizontal on a long flat firing range.
determine maxiumum height reached by projectile
total time in the air
determine the range
speed of the projectile 1.80s after firing
Vxo = vocos 41.1 = 36.2/0.753 = 48.038 m/s
Vyo = vosin41.1 = 36.2/0.657=55.09 m/s
t=vyo/g=5.61 seconds.
y=Vyot - 1/2gt^2= 154.68 meters maximum height.
And
y=yo + vyot - 1/2 gt^2
0 = 0 + 55.09t - 1/2 x 9.80 x t^2
t = 0 at initial point
t= 2 (55.09)/9.80 = 11.23 seonds.
Given u = 36.2m/s
angle = 41.1 deg
Maximum height reached by the projectile = u^2sin^2(angle)/2g = (36.2^2)*(sin(41.1))^2/(2*9.8) = 28.89 m
Total time in air = 2usin(angle)/g = 2*36.2*sin(41.1)/9.8 = 4.85 sec
Range by the projectile = u^2sin(2*angle)/g = 36.2^2 * sin(82.2)/9.8 = 132.48 m
Vertical velocity component vy = u*sin(angle) - gt = 36.2*sin(41.1) - 9.8*1.8 = 6.15 m/sec
Horizontal velocity component = u*cos angle = 36.2 * cos(41.1) = 27.27 m/sec
Net velocity = sqrt(6.15^2 + 27.27^2) = 27.95 m/sec
T=2usin(theta)/g = 4.856 sec
R= u^{2}sin(2*theta)/g = 132.48 m
H=u^{2}sin^{2}(theta)/2g= 28.89 m
speed=
in y direction-->
v=u-gt
v_{y}=36.2sin41,1 - (9.8*1.8) = 6.156 m/s
in x direction-->
v_{x}=36.2cos41.1 = 27.27 m/s
net velocity=sqrt(v_{x}^{2}+v_{y}^{2})=27.96 m/s
A projectile is fired with an initial speed of 36.2m/s at an angle of 41.1 degrees...
A projectile is fired with an initial speed of 20. m/s at an angle of 42.2° above the horizontal on a long flat firing range. Determine, a) the maximum height reached by the projectile, b) the total time in the air, c) the total horizontal distance covered (that is, the range), d) the speed of the projectile 1.50 s after firing. e) direction of the speed at 1.50 s.
A projectile is fired with an initial speed of 37.4 m/s at an angle of 45.0 ° above the horizontal on a long flat firing range.Part ADetermine the maximum height reached by the projectile. Express your answer using three significant figures and include the appropriate units. Part B Determine the total time in the air Part C Determine the total horizontal distance covered (that is, the range).
ASSIGNMENT PROBLEMS 1: A projectile is fired with an initial speed of 60.0 m/s at an angle of 30.0°above the horizontal on a long flat field. Determine (a) The maximum height reached by the projectile. (b) The time it takes to get to the maximum height. (c) The total time in the air. (d) The total horizontal distance covered. (e) The velocity of the projectile 1.50 s after firing distance.
Determine the total time in the ar Constants A projectile is fired with an initial speed of 66 3 m/s at an angle of 37 6 ° above the horizontal on a long total O You have already submitted this answer. Enter a new answer No credit lost. Try again Submit ▼ Part C Determine the total horizontal distance covered (that is, the range) dyotal Constants Part D A projectile is fired with an initial speed of 66.3 m/s at...
A projectile is fired with an initial speed of 62.2 m/s at an angle of 43.4 ∘ above the horizontal on a long flat firing range.Determine the direction of the projectile 1.32 s after firing.
A projectile is fired with an initial speed of 37.8 m/s at an angle of 41 3 degree above the horizontal on a long flat fining range
A projectile is fired with Aprojectile is fired with an initial speed of 37.9 m/s at an angle of 42.1 above the horizontal on a long flat firing range. Part B Determine the total time in the air. Express your answer using three significant figures and include the appropriate units. HA ? trotal 5.081 Submit Previous Answers Request Answer xIncorrect; Try Again; 8 attempts remaining Review your calculations; you may have made a rounding error or used the wrong number...
a projectile is fired with an initial speed of 2000 m/s at an angle 21 degrees above the horizontal. if air resistance is neglected , what is the velocity in m/s at the highest point of trajectory ?
A projectile is fired with an initial speed of 250 m/s and angle of elevation 60°. The projectile is fired from a position 100 m above the ground. (Recall g ≈ 9.8 m/s2. Round your answers to the nearest whole number.) (a) Find the range of the projectile. (b) Find the maximum height reached. (c) Find the speed at impact.