Question

A parallel plate capacitor is constructed with plate area of 0.40 m² and a plate separation of 0.10 mm. How much charge is stored on it when it is charged to a potential difference of 12 V?

A parallel-plate capacitor is filled with air, and the plates are separated by 0.050 mm. If the capacitance is 17.3 pF, what is the plate area?

A parallel plate capacitor is constructed with plate area of 0.0010 m² and a plate separation of 0.50 mm. When it is charged to a potential difference of 12 V, the charge stored on it is " " x10^-10 C.  

Answer 1

a)

capacitance, C = epsilon _ not * A / d = 8.85*10^-12 * 0.4 / (0.1*10^-3)

C = 3.54*10^-8

charge, Q = CV

Q = 3.54*10^-8* 12

Q = 4.248*10^-7 C

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b)

C = epsilon_not * A / d

17.3*10^-12 = 8.85*10^-12* A / (0.05*10^-3)

A = 9.77 *10^-5 m^2

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C = 8.85*10^-12* 0.001 / (0.5*10^-3)

C = 1.77* 10^-11 F

Q = CV = 12 *1.77*10^-11

Q = 2.124*10^-10 C

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