Question

Two rocks are thrown from the top of a very tall tower. One of them is thrown horizontally to the left with an initial velocity of Vieft = 15.4 m/s. The other rock is thrown horizontally to the right with an initial velocity of Vright = 13.0 m/s. (See figure.) 

How far will the rocks be from each other after 5.88 s? 

Answer 1

Horizontal distance covered by 1^st rock to the left which will be given as -

d_left = v_left . t

d_left = [(15.4 m/s) (5.88 s)]

d_left = 90.552 m

Horizontal distance covered by 2^nd rock to the right which will be given as -

d_right = v_right . t

d_right = [(13 m/s) (5.88 s)]

d_right = 76.44 m

How far will the rocks be from each other after 5.88 sec?

we know that, d = d_left + d_right

d = [(90.552 m) + (76.44 m)]

d = 166.9 m

d 167 m