What is the force F⃗ on the 1.3 nC charge in themiddle of (Figure 1) due...

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Question

Figure 1 of 1 一2.0 nC 2.0 nC 1.0 cm 1.0 cm 2.0 nC 2.0 nC

What is the force F⃗ on the 1.3 nC charge in the middle of (Figure 1) due to the four other charges? Give your answer in component form.

Enter the x and y components of the force separated by a comma.

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Answer 1

Answer #1

Here ,

distance between corner and center , d = 1/sqrt(2) = 0.707 cm

Now , for the force on the center charge due to diagonally oposite charges

F1 = 9 *10^9 * 1.3 *10^-9 * (2 + 2)*10^-9/(0.707 *10^-2)^2

F1 = 9.36 * 10^-4 N

Now, charge at the second diagonal will have force as well

F2 = 9.36 * 10^-4 N

for the net force , as F1 and F2 are perpenicular to each other

Fnet = sqrt(9.36^2 + 9.36^2) * 10^-4 N

Fnet = 1.33 *10^-3 N

as the direction of force is negative x axis

hence , the x-component = -1.33 *10^-3 N

y-component = 0 N

Answer 2

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