Question

A projectile is fired from level ground with an initial speed of 24.3 m/s at a launch angle of 32 degrees relative to the horizontal direction. Where does the projectile land if you ignore air resistance? (Assume 3 significant digits).^ (2)

Answer 1

initial velocity of the projectile, - U = 24.3 m/s. 0 = 32 So vertical component of the initial velocity, y= u bo sino x ote velocity, horizontal intal component of the initial 1 Use= uloso vertical component of acceleration, ay = g. horizontal component of accelerations, an=0. S ha nyt + tayt? Dr. for Total time of flight of, h=0 - MyT + 2 ayt? 0 - Uy = fapt »T 24g) (2x - CAĐN - (2u Suo). Range of the projectile, R = Ua T = Ucoso (2a sino) = siul20) 2 °2413) sin640). (54.00m The projectile lands at a distance 54,10m horizontally from the point of throw of the projectile