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A cannon is fired over level ground at an angle of 30 degrees to the horizontal....

A cannon is fired over level ground at an angle of 30 degrees to the horizontal. the initial velocity of the cannonball is 400 m/s but because the cannon is fired at an angle, the vertical component of the velocity is 200 m/s and the horizontal component is 346 m/s

a. How long is the cannonball in the air (use 10 m/s^2 and the fact thatthe total time of flight is twice the time required to reach the high point.

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Answer #1

Vertical Velocity. uy = 200m/s

Accln = 10m/s2 downwards

Time to reach top most point = uy/ g = 200/10 = 20s

Total time = 2 x 20 s = 40s

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