
Two forces, F1 and
F2, act on the m = 7.29 kg
block shown in the figure above.
The magnitudes of the forces are F1 = 62.0 N and F2 = 36.4 N. theta = 68.6 deg. What is the magnitude of the horizontal acceleration of the block?
that's easy we know that
force = mass * acceleration
acceleration = force / mass
acceleration = ( 36.4 N - 62.0 N * cos ( 68.6) ) / ( 7.29 kg ) = 1.8899 m/s^2 or 1.900m/s^2 ==========answer)
Two forces, F1 and F2, act on the m = 6.50 kg block shown in the
drawing below.
The magnitudes of the forces are F1 = 64.7 N
and F2 = 31.7 N. θ = 73.5°. What is the
magnitude of the horizontal acceleration of the block?
Two forces F1 and F2 act on a 6.20-kg object. F1 = 25.0 N and F2 = 16.0 N.(a) Find the acceleration of the object for the configuration of forces shown in Figure (a). (b) Find the acceleration of the object for the configuration of forces shown in Figure (b).
two forces F1 and F2 act on a 6.80-kg object. F1=30.0 N and F2 = 11.0 N. (a) Find the acceleration of the object for the configuration of forces shown in figure (a)(b) Find the acceleration of the object for the configuration of forces shown in Figure (b).
Two forces, F1 and F2, act on a 1.00 kg object where F1 = 20.0 N and F2 = 12.0 N. (a) Find the acceleration in Figure P5.11a(b) Find the acceleration in Figure P5.11
Two forces, of magnitudes F1 = 95.0 N and F2 = 45.0 N , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1) Initially, the center of the block is at position xi = -1.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 6.00 cm . Part A Find the work W1 done on...
1) Two forces F1 and F2 acting on a 40 kg crate have values 150 N and 210 N respectively. The angle between them is 50 degree, with F1 acting in the horizontal direction, as shown in the diagram below. Calculate a) the horizontal component acceleration of the block b) the vertical component acceleration of the block c) the magnitude and direction of the total acceleration
A 10 kg object on a frictionless table is subjected to two horizontal forces, F1 and F2, with magnitudes F1 = 22 N and F2 = 38 N, as shown in Figure 4-28. 10kg 30 Figure 4-28 (a) Find the acceleration a of the object (0.3 (b) A third force F3 is applied so that the object is in static equilibrium. Find F3 x i)m/s2 i1.64545 X (-41 x i) N |-32.909
A 10 kg object on a frictionless table...
15.5
Two forces, of magnitudes F1 = 80.0 N and F2 = 20.0 N , act in
opposite directions on a block, which sits atop a frictionless
surface, as shown in the figure. (Figure 1)Initially, the center of
the block is at position xi = -1.00 cm . At some later time, the
block has moved to the right, and its center is at a new position,
xf = 1.00 cm
A.
Find the work W1 done on the block...
The
two forces F1 and F2 shown in figure 1 act on a 23.0kg object on a
frictionless tabletop. Suppose that F1 = 12.0 N and F2 = 18.8 N.Determine the magnitude of the net force on the object for the
diagram (a) in the figure.
two forces f1 and f2 act on a 5kg object as shown in the figures. if f1 = 20 n and f2 = 15.0 n find the acceleration in each case (a) 180 degrees (b) 140 degrees (C) 40 degrees