Question

Consider a parallel-plate capacitor that is partially filled with a dielectric of dielectric constant K. The dielectric has the same same height as theseparation of the plates of the capacitor butfills a fraction f of the area of the capacitor. The capacitance of thecapacitor whenthe dielectric is completely removed is C₀.

What is the capacitance C(f) of this capacitor as afunction of f? Express C(f) in terms of C₀, f,and K.

Answer 1

C(f) = C₀((1-f)+fk)

For starters, the area of the slabs is equivalent to 1-f and f with each slab having an initial charge of C₀ and the slab with an area of 'f' having the dielectric on it "k"