Question

2. An automobile accelerates from zero to 36.72 m/s in 6.80 s. The wheels have a diameter of 0.450 m What is the average angular acceleration of each wheel? 

3. Convert 2 600 rev/min to rad/s 

4. A grindstone spinning at the rate of 8.3 rev/s has what approximate angular speed?

Answer 1

2)

Acceleration, a = (v - u)/t = (36.72 - 0)/6.80 = 5.4 m/s^2

Angular acceleration, alpha = 5.4/(0.45/2) = 24 rad/sec^2

3)

2600 rev/min = 2600 x 2 pi/60 = 272.27 rad/sec

4)

8.3 rev/sec = 8.3 x 60/2 pi = 79.26 rpm

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