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The concept required to solve this problem is Lenz’s law.
Use the Lenz’s law and right hand thumb rule to find the induced current direction and magnetic flux direction.
Lenz’s law stats that the current induced in a conducting material by changing magnetic flux will create a magnetic field exactly opposite to the change in the applied field.
The right-hand thumb rule gives the direction of magnetic flux due to a current loop is given by the thumb if fingers curl in the direction of magnetic flux or vice versa.
(A)
When the switch is open no current flows through the electromagnet coil. There is no magnetic field produced by the electromagnet. So, there is no applied field which implies there is no magnetic flux or change. So, the magnetic flux is not positive or negative but zero. Thus, there is no magnetic flux through the wire loop.
(B)
When the switch is open no current flows through the electromagnet coil. There is no magnetic field produced by the electromagnet. So, there is no applied field which implies there is no magnetic flux or change in magnetic flux. The current is induced only if the magnetic flux through the loop changes. Thus, there is no induced current.
(C)
When the switch is closed, the current flows or increases through the electromagnet from positive terminal to negative terminal of the battery. The direction of flow of current in the electromagnet is counterclockwise from the left view.
The magnetic flux from the electromagnet therefore increase is towards right as thumb points towards right when fingers curl counterclockwise.
From the Lenz’s law, the induced magnetic flux opposes the increase in the magnetic flux. So, the magnetic flux is induced towards left. From the right-hand rule, again the thumb point towards left so the fingers in counterclockwise direction or the induced current is in counterclockwise direction.
(E)
When the switch is closed, the current flows or increases through the electromagnet from positive terminal to negative terminal of the battery. The direction of flow of current in the electromagnet is clockwise from the left view. The magnetic flux from the electromagnet therefore increases towards left as thumb points towards left, when fingers curl clockwise. From the Lenz’s law, the induced magnetic flux opposes the increase in the magnetic flux. So, the magnetic flux is induced towards right. From the right hand rule again, the thumb point towards right so the fingers in clockwise direction or the induced current is in clockwise direction.
(F)
When the switch is reopened, the current decreases through the electromagnet till it becomes zero from positive terminal to negative terminal of the battery. The direction of flow of current in the electromagnet is clockwise from the left view. The magnetic flux from the electromagnet therefore decreases towards left as thumb points towards left, when fingers curl clockwise.
From the Lenz’s law, the induced magnetic flux opposes the decrease in the magnetic flux. So, the magnetic flux is induced towards left. From the right hand rule again, the thumb point towards left so the fingers in counterclockwise direction or the induced current is in counterclockwise direction.
Ans: Part AThere is no magnetic flux through the wire loop.
Part BThere is no induced current.
Part CThe induced current is counterclockwise.
Part EThe induced current is clockwise.
Part FDecreases, Counterclockwise
In this problem, you will use Lenz's law to explore what happenswhen an electromagnet is activated...
Part D
Finally, the switch on the electromagnet is reopened. The
magnitude of the external magnetic flux through the wire loop
______ (A. increases, B. decreases, C. remains constant), and there
is _______ (A. zero, B. a clockwise, C. a counterclockwise) current
induced in the loop (as seen from the left).
Enter the letters corresponding to the responses that correctly
complete the statement above. For example, if the correct answers
are A and C, type A,C
________________
Now consider the...
Part D
Finally, the switch on the electromagnet is reopened. The
magnitude of the external magnetic flux through the wire loop
______ (A. increases, B. decreases, C. remains constant), and there
is _______ (A. zero, B. a clockwise, C. a counterclockwise) current
induced in the loop (as seen from the left).
Part F
Now the switch on the electromagnet is
reopened. The magnitude of the external magnetic flux through the
wire loop ______ (A. increases, B. decreases, C....
In this problem, you will use Lenz's law to explore what happens when an electromagnet is activated a short distance from a wire loop. You will need to use the right-hand rule to find the direction of the induced current. When the switch is open, which of the following statements about the magnetic flux through the wire loop is true? Assume that the direction of the vector area of the wire loop is to the right. There is no magnetic...
The switch on the electromagnet, initially open, is closed. What is the direction of the induced current in the wire loop (as seen from the left)? There is no induced current The induced current is clockwise. The induced current is counterclockwise. Submit Request Answer In this problem, you will use Lenz's law to explore what happens when an electromagnet is activated a short distance from a wire loop. You will need to use the right-hand rule to find the direction...
To practice Tactics Box 25.1
Using Lenz's law. Lenz's law is a useful rule for determining the
direction of the induced current in a loop. Specifically, it says
that there is an induced current in a closed conducting loop if and
only if the magnetic flux through the loop is changing. The
direction of the induced current is such that the induced magnetic
field opposes the change in the flux. The following Tactics Box
summarizes the essential steps in using...
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