Question

A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectively.
a. determine the initial speed of the projectile
b. at what angle is the projectile fired (measured with respect to the horizontal)?
c. approximately how long does it take the projectile to reach the highest point in its trajectory?

Answer 1

Given that the componnts of velocities are 30 m/s and 40 m/s

a)so their resultant velocity is v=√30²+40²

                                               =50 m/s

b)angd the angle is θ=tan^-1(40/30)

                                =53.13 deg

c)the time taken to reach maximum height

    t=v/g

     =

       5.10s