#!/bin/bash
echo "#########Bash script to print number of arguments and list of
command line arguments##########"
echo "Number of argumnets: $#"
echo "List of command line arguments are: "
for arg in $*; do
echo $arg
done
######################################
#output
#########Bash script to print number of arguments and list of
command line arguments##########
Number of argumnets: 4
List of command line arguments are:
this
is
to
test
Write a bash shell script to print the number of command line arguments and list of...
Write a bash shell script called direct.sh. This script will take an arbitrary number of command line arguments. Your script should create directories starting with the first argument, then the second directory inside the first one, and then the next one inside the second one, and so on.
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Unix classes
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