here,
let the velocity at the bottom of the track is v
Using conservation of energy
0.50 * m * v^2 = m * g * H
0.50 * v^2 = 9.8 * 24
v = 21.7 m/s
for the maximum height h
maximum height h = (v * sin(theta))^2/(2 * g)
maximum height h = (21.7 * sin(28))^2/(2 * 9.8)
maximum height h = 5.29 m
the maximum height is 5.29 m
part (b)
as the speed is independent of mass
the height remains the same
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