The electric field 10.0 cm from the surface of a copper ball of radius 5.0 cm...
The electric field 10.0 cm from the surface of a copper ball of radius 5.0 cm is directed toward the ball’s center and has magnitude 9.0x 10^2 N/C. How much charge is on the surface of the ball?
Homework Answers
Area, A = 4 pi r^2 = 4 pi x 0.1^2 = 0.126 m^2
Charge, q = e0 A E
q = (8.85 x 10^-12)(0.126)(900) = -1 x 10^-9 C
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