Question

Last 15 points (1 point/question unless noted otherwise.) 1. Draw the missing lone pairs on the structure shown in Figure 1. OCH 2. Carbon 1 has _hybridization, HC CH, 2 7 molecular geometry, and bond angle(s) of N° 3. The nitrogen has hybridization, H. CH molecular geometry, and bond angle(s) of Figure 1. DEET (N,N-diethyl-meta-toluamide or N,N- 4. The carbon indicated by the arrow has diethyl-3-methylbenzamide) is the active ingredient in hybridization, many mosquito repellents. For more information, see Paul May, Molecule of the Month January 2011 http://www.chm.bris.ac.uk/motm/DEET/dech.htm molecular geometry, and bond angle(s) of 5. The DEET molecule has sigma (6) bonds and pi (r) bonds. 6. In the trigonal bipyramidal arrangement, why does a lone pair occupy an equatorial position rather than an axial position? Multiple Choice: 7. Which compound has the largest dipole moment (.e., is the most polar)? (A) CH (B) CH31 (C) CH Br (D) CH,CI (E) CHF 8. Indicate the type of hybrid orbitals used by the central atom in TeF4. (A) sp (B) sp (C) sp (D) spd (E) sp'd

Answer 1

0 Ans : lone pairs are shown by red dots. Hyco -? HC CH Hzc - CH3 UI In general, hybeeidisation = $no. of o bond (8) + no. of lone pair (s) 3 af carbon 1 Hybeldisation = 36 honds) to ( lone pair) . = 3(3p2 ) Moleualan geometry = tsciangular planar Band angle = 1200 Af Nitrogen : Hybedisalim = 3(r bonds) + 2 lp = 4 (p= fone pair(s) ] = 8b3 hybsurdisation Molecular geometry = Treigonal pys-amidal Bond angle a 107° SETE

© Carbon indicated by arrow Hybsadisation = 4(bonds) to (lp) = 4 = 8f3 hykowdization Molecular geometry = Tetrahedral Bond angle = 109° 28' . It 0 EV sa CON- 14 4-6 4- 4 HH If bonds between two atoms are single bond , it is called a r bond. The multiple bonds (leke Hand double bond, double bond ete.) auses due to T bond formation. Thus, Total no. of o bond = 28 - Total no. of in bond = 4 o Let us consider one structure has while other has two situations in which lone pair on anial quatorial

LA uokrat llane Here at lp-bp seepulsion you Here lp-bp refulsion is more because there are present at soo. W No. of ep-bp 9tebul,1 м at goo 2 repulsion at equatorial planade, of 120° Accorcling to VSEPR model lp- lp > Sp- bp > bp-bp Sp- bp repulsions at gue is more in structure(I). So, it is less stable. This is why lone pair occupy equatorial position rather than axial

THERE 1=0 # OLO H TE H . My to M370 F>6> I (F(-4) (-I Order of clechonegativity : polaruty of (-x bond (* = F, G, I). clipole moment order = correct option : ② M3 > N2 > S Tefy Te(52) = [kr] 4 dº 58 5pf 55 5d TREAM VSEC of Te in Te in = [1] (en 5b 141411 Tefa TA het he in enuted salt) le olalar) sp?hyboci disation Correct option : ③ .