Question

Please label all the values and equations used to solve the problem. Also, please box the final answer(s).

3. Nuclear binding: Find the total and per-nucleon nuclear binding energies for: (a) 82° Pb, (b) Fe, (c) Ca.

Answer 1

solution: The binding energy of a nucleus having z protons and N neutrons is defined as: E = ( 2 Mp + Nmm - AM) er where AM is the mass of given atom. Mois mass of proton, mis mass of Neutron and = 931.5 Mevlu (a) For 208 82Pb , Z = 82 , N=126 Mer = 207.9766521 U M = 1.00727647 u Mo: 1.0086654 U. 00727647) + (126x8.0086654) - 207.97665217x931-5 E = 1594.596509 Men Mev

in Binding energy per nucleon of 20806 is : fb . 1594.596509 208 Ene - - 208 B = 7.666329 Mer Men 26 , Z=26, N=30 A M = 55.9349375 u. Binding energy, Ep = [(2631-0727 647) +(302 1008657) – 55.9349375] u 160 = 478.989 mer in Binding energy per nucleon of store is B = 8.552377 Mer

for Aca 1 ao ca 20 / Z=20, N=20 a = 39.962591 v Binding of energy, 66 = (20 31.007276418) +(2034 1.008 657) – 39.96291) 2915 = 331.918973 Mev Now , binding energy per nucleon, 1996 = 8.2.97974 mer 4 Mer -
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