here,
the velocity of Juan , v1 = 7.4 m/s j
the velocity of ball , v2 = 12.2 m/s * ( sin(32) i + cos(32) j)
v2 = 6.47 i m/s + 10.35 j m/s
the velocity of ball relative to Juan , v21 = v2 - v1
v21 = 6.47 i m/s + 2.95 j m/s
a)
the magnitude of velocity of ball relative to Juan , |v21| = sqrt(6.47^2 + 2.95^2) = 7.11 m/s
b)
the direction , theta = arctan(2.95/6.47) = 24.5 degree North of East
Part A and B Part A Constants In a World Cup soccer match, Juan is running...
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Suppose a soccer player boots the ball from a distance 33.5 m toward the goal. find the initial speed of the ball if it just passes over the goal,2.4 m above the ground, given the initial direction of 40 degrees above the horizontal.
please do part a and b, thank you.
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