A force <30, 0, 0> N acts for 0.2 seconds on an object of mass 1.2...

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A force <30, 0, 0> N acts for 0.2 seconds on an object of mass 1.2 kg whose initial velocity was <0, 25, 0> m/s. What is the

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Answer 1

Answer #1

The expression for the final velocity is, Ve = v; + at F =v+ m Vr = (0,25,0) m/s + 30,0,0) N (0.2 s) 1.2 kg = (0,25,0) m/s +(

Answer 2

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